Handle Mallet
Handle Mallet
Check out this page if you are looking for Handle Mallet
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![]() 24 oz Rubber Mallet with Fiberglass Handle US $13.95
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![]() 32oz RUBBER MALLET WITH WOODEN HANDLE NEW US $14.41
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![]() 031M Long Antiskid Handle Black Rubber Mallet Hammer US $25.29
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![]() TOOLS RUBBER MALLET WOODEN HANDLE US $7.99
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![]() Hammer 16oz or 8oz Fiberglass Steel or Wood Claw Rip or Mallet US $4.00
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![]() DIY TOOL Rubber Mallet Hammer Nonslip Handle Non Marking 500g 1764oz US $10.50
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![]() Home Work Black Rubber Mallet Hammer w Nonslip Handle US $17.30
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![]() TOOL RUBBER MALLET 1 LB WOOD HANDLE GOOD QUALITY NEW US $4.24
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![]() Large 2 lb Wood Handle Rubber Mallet US $9.99
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Center of Mass and Translational Momentum?
A mallet consists of a uniform cylindrical head of mass 2.00 kg and a diameter 0.0800 m mounted on a uniform cylindrical handle of mass 0.500 kg and length 0.240 m. If this mallet is tossed, spinning, into the air, how far above the bottom of the handle is the point that will follow a parabolic trajectory?
I don't see how the masses factor in...
it is the center of mass that will follow a parabolic trajectory
the coordinate of the center of mass is:
ycm=(m1 y1+m2 y2)/(m1+m2)
where m1, m2 are the masses of the handle, mallet, and y1, y2 are the coordinates of their individual centers of mass
since we are told the mallet and handle are uniform, we can treat them as point masses with the mass concentrated at the center of mass of each individual component
so, the y coordinate of the handle's center of mass is 0.12m; and for the mallet it is 0.04 + 0.24 = 0.28m (since the mallet is mounted at the end of the handle)
the y coordinate of the center of mass for the whole system is:
ycm=(0.5kg x 0.12m + 2kg x 0.28m)/(0.5kg+2kg)
ycm=0.248 m
and this point, just above the end of the handle, is the point that will follow a parabolic trajectory


US $4.99








































